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13. Calculus II: Trigonometric Integrals (Level 7 of 7) | Identities, Conjugate, Factoring
This video concludes the methods for solving trigonometric integrals that contain combinations of sine and cosine. This video covers 4 challenging examples that require the use of different trigonometric identities, multiplying by the conjugate, and factoring.

12. Calculus II: Trigonometric Integrals (Level 6 of 7) | Product to Sum Identities
This video continues illustrating methods for solving trigonometric integrals that contain combinations of trigonometric functions. Specifically, those that contain products of sine and cosine with distinct arguments (angles). This video covers 3 examples illustrating the use of the product to sum identities for sine and cosine.

11. Calculus II: Trigonometric Integrals (Level 5 of 7) | Even Power on Sine and Cosine II
This video continues illustrating methods in solving trigonometric integrals that contain combinations of trigonometric functions. Specifically, those that contain powers of sine and cosine. This video covers 2 challenging examples illustrating the case when the power of sine and cosine are even.

10. Calculus II: Trigonometric Integrals (Level 4 of 7) | Even Power on Sine and Cosine I
This video is an introduction to solving trigonometric integrals that contain combinations of trigonometric functions. Specifically, those that contain powers of sine and cosine. This video covers 2 basic example illustrating the case when the power of sine and cosine are even.

9. Calculus II: Trigonometric Integrals (Level 3 of 7) | Odd Power on Sine and Cosine
This video is an introduction to solving trigonometric integrals that contain combinations of trigonometric functions. Specifically, those that contain powers of sine and cosine. This video covers 1 basic example illustrating the case when the power of sine and cosine are odd.

8. Calculus II: Trigonometric Integrals (Level 2 of 7) | Odd Power on Sine
This video is an introduction to solving trigonometric integrals that contain combinations of trigonometric functions. Specifically, those that contain powers of sine and cosine. This video covers 4 basic examples illustrating the case when the power of sine is odd.

7. Calculus II: Trigonometric Integrals (Level 1 of 7) | Odd Power on Cosine
This video is an introduction to solving trigonometric integrals that contain combinations of trigonometric functions. Specifically, those that contain powers of sine and cosine. This video covers 4 basic examples illustrating the case when the power of cosine is odd.

6. Calculus II: Integration By Parts (Level 6 of 6) | Definite Integrals II
This video goes over two examples, covering the proper way to find definite integrals that require the use of multiple integration techniques. Specifically, integration by parts and u-substitution.

5. Calculus II: Integration By Parts (Level 5 of 6) | Definite Integrals I
This video goes over three examples, covering the proper way to find definite integrals that require the application of the integration by parts formula. An example covering the tabular method is also presented.

4. Calculus II: Integration By Parts (Level 4 of 6) | Constant Multiple
This video goes over an example, covering the proper way to find integrals that require the repeated application of the integration by parts formula specifically an integral that generates a constant multiple of the original integral. In addition, this integral will also be found by using the tabular method for integration by parts.

3. Calculus II: Integration By Parts (Level 3 of 6) | Tabular Method, Escalante's Method
This video goes over 2 examples, covering the proper way to find integrals that require the repeated application of the integration by parts formula. In addition, the tabular method for integration by parts is also introduced.

2. Calculus II: Integration By Parts (Level 2 of 6) | Two Forms of Formula
This video goes over 3 examples, covering the proper way to use the integration by parts formula. This video includes an example covering the two forms of the integration by parts formula, an example where rewriting of the integrand is required, and a final example where an integral contains a single function.

1. Calculus II: Integration By Parts (Level 1 of 6) | Formula, Example
This video goes over a second integration technique used to find indefinite integrals formed by a product of functions. This video goes over the derivation of the integration by parts formula by using the product rule as a starting point. In addition, the video goes over an example covering the application of this new integration technique.
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